Perbaikan PTS - Pembahasan Soal - X MIPA 2 - Hana Krissintadewi
1. Himpunan Penyelesaian |2x - 7| = 3 |2x - 7| = 3 atau |2x - 7| = -3 2x = 3 + 7 2x = -3 + 7 2x = 10 2x = 4 x = 5 x = 2 HP = {2, 5} 2. Himpunan Penyelesaian |2x - 1| = |x + 4| |2x - 1| = |x + 4| atau |2x - 1| = -|x + 4| 2x - x = 4 + 1 2x - 1 = -x - 4 x = 5 2x + x = -4 + 1 3x = 3 x = 1 HP = {1, 5} 3. Himpunan Penyelesaian |x + 7/2x - 1| = 2 |x + 7| = 2 |2x - 1| |x + 7| = |2 (2x - 1)| x + 7 = 4x - 2 atau x + 7 = -4x - 2 x - 4x = -2 - 7 x + 4x = -2 - 7 -3x = -9 5x = -9 x = 3 x = -9/5 > 1 -4/5 HP = {1 -4/5,